What amount of torque is produced by a hydraulic motor generating a pressure of 1770 psi with a 25 gpm pump at 1200 rpm?

To determine the torque produced by a hydraulic motor, you can use the formula that relates hydraulic power to both flow rate and pressure. The formula is:

[ \text{Power (hp)} = \frac{\text{Pressure (psi)} \times \text{Flow Rate (GPM)}}{1714} ]

This will allow us to calculate the hydraulic power in horsepower. From there, we can calculate the torque using the relationship between power, torque, and rotational speed:

[ \text{Torque (ft-lbs)} = \frac{\text{Power (hp)} \times 5252}{\text{RPM}} ]

First, let's calculate the power in horsepower:

• Pressure = 1770 psi

• Flow Rate = 25 gpm

Plugging these values into the power formula:

[ \text{Power} = \frac{1770 \times 25}{1714} ]

[ \text{Power} \approx 25.85 \text{ hp} ]

Next, we can calculate the torque at 1200 rpm:

[ \text{Torque} = \frac{25.85 \times 5252}{1200} ]

[ \text{Torque} \