If 500 psi is applied to the low-pressure side of an intensifier cylinder with an input area of 10 sq in, what is the force in pounds?

To calculate the force exerted by the low-pressure side of an intensifier cylinder, you can use the formula:

Force = Pressure × Area

In this scenario, the pressure applied is 500 psi (pounds per square inch) and the area of the input side is 10 square inches.

Substituting the values into the formula:

Force = 500 psi × 10 sq in = 5000 lbs

This computation shows that the force exerted on the low-pressure side of the intensifier cylinder is indeed 5000 pounds. Therefore, this makes the option indicating 5000 lbs the correct answer.

Understanding this principle is essential as it illustrates the direct relationship between pressure, area, and force within hydraulic systems, which is a fundamental concept in millwright and mechanical applications.